SyntaxTrivia.Equals 方法

定义

重载

Equals(SyntaxTrivia)

确定提供的 SyntaxTrivia 是否等于此 SyntaxTrivia值。

Equals(Object)

确定提供的 SyntaxTrivia 是否等于此 SyntaxTrivia值。

Equals(SyntaxTrivia)

Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs

确定提供的 SyntaxTrivia 是否等于此 SyntaxTrivia值。

public:
 virtual bool Equals(Microsoft::CodeAnalysis::SyntaxTrivia other);
public bool Equals (Microsoft.CodeAnalysis.SyntaxTrivia other);
override this.Equals : Microsoft.CodeAnalysis.SyntaxTrivia -> bool
Public Function Equals (other As SyntaxTrivia) As Boolean

参数

other
SyntaxTrivia

返回

实现

适用于

Equals(Object)

Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs
Source:
SyntaxTrivia.cs

确定提供的 SyntaxTrivia 是否等于此 SyntaxTrivia值。

public:
 override bool Equals(System::Object ^ obj);
public override bool Equals (object obj);
public override bool Equals (object? obj);
override this.Equals : obj -> bool
Public Overrides Function Equals (obj As Object) As Boolean

参数

obj
Object

返回

适用于