InOutArgument<T>.FromExpression 方法

定义

命名空间:

System.Activities

程序集:

System.Activities.dll

初始化和返回使用指定的 InOutArgument<T> 构造的新 Activity<TResult>。

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);

public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);

static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>

Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

参数

expression

Activity<Location<T>>

参数的值。

返回

InOutArgument<T>

新自变量。