Size3D.Equality(Size3D, Size3D) 运算符

定义

比较两个 Size3D 结构是否相等。 如果两个 Size3D 结构的 XYZ 属性的值相同,则两个结构相等。

public:
 static bool operator ==(System::Windows::Media::Media3D::Size3D size1, System::Windows::Media::Media3D::Size3D size2);
public static bool operator == (System.Windows.Media.Media3D.Size3D size1, System.Windows.Media.Media3D.Size3D size2);
static member ( = ) : System.Windows.Media.Media3D.Size3D * System.Windows.Media.Media3D.Size3D -> bool
Public Shared Operator == (size1 As Size3D, size2 As Size3D) As Boolean

参数

size1
Size3D

要比较的第一个 Size3D 结构。

size2
Size3D

要比较的第二个 Size3D 结构。

返回

如果 size1size2XYZ 分量相等,则为 true;否则为 false

示例

以下示例演示如何使用重载相等运算符检查两 Size3D 个结构是否相等。

// Checks if two Size3D structures are equal using the overloaded == operator. 
// Returns a Boolean.

// Declaring Size3D structure without initializing x,y,z values
Size3D size1 = new Size3D();

// Declaring Size3D structure and initializing x,y,z values
Size3D size2 = new Size3D(5, 10, 15);
Boolean areEqual;

// Assigning values to size1
size1.X = 2;
size1.Y = 4;
size1.Z = 6;

// Checking for equality
areEqual = size1 == size2;

// areEqual is False

// Displaying Results
syntaxString = " areEqual = size1 == size2;";
resultType = "Boolean";
operationString = "Checking if two Size3D structures are equal";
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString);
' Checks if two Size3D structures are equal using the overloaded == operator. 
' Returns a Boolean.

' Declaring Size3D structure without initializing x,y,z values
Dim size1 As New Size3D()

' Declaring Size3D structure and initializing x,y,z values
Dim size2 As New Size3D(5, 10, 15)
Dim areEqual As Boolean

' Assigning values to size1
size1.X = 2
size1.Y = 4
size1.Z = 6

' Checking for equality
areEqual = size1 = size2

' areEqual is False

' Displaying Results
syntaxString = " areEqual = size1 == size2"
resultType = "Boolean"
operationString = "Checking if two Size3D structures are equal"
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString)

注解

由于值在对其执行算术运算时可能会失去精度,因此 Double 在逻辑上相等的两 Size3D 个实例之间的比较可能会失败。

适用于

另请参阅