Tuple<T1,T2,T3>.Item3 Tuple<T1,T2,T3>.Item3 Tuple<T1,T2,T3>.Item3 Tuple<T1,T2,T3>.Item3 Property

Definizione

Ottiene il valore del terzo componente dell'oggetto Tuple<T1,T2,T3> corrente.Gets the value of the current Tuple<T1,T2,T3> object's third component.

public:
 property T3 Item3 { T3 get(); };
public T3 Item3 { get; }
member this.Item3 : 'T3
Public ReadOnly Property Item3 As T3

Valore della proprietà

T3 T3 T3 T3

Valore del terzo componente dell'oggetto Tuple<T1,T2,T3> corrente.The value of the current Tuple<T1,T2,T3> object's third component.

Esempi

Nell'esempio seguente viene definita una matrice Tuple<T1,T2,T3> di oggetti che contengono i nomi degli studenti, i punteggi di test medi e il numero di test eseguiti.The following example defines an array of Tuple<T1,T2,T3> objects that contain the names of students, their average test scores, and the number of tests taken. La matrice viene passata al ComputeStatistics metodo, che calcola il Punteggio medio, la deviazione standard e il numero di case da cui vengono calcolate le statistiche.The array is passed to the ComputeStatistics method, which calculates the mean score, standard deviation, and number of cases from which the statistics are calculated. Questi valori vengono archiviati nell' Tuple<T1,T2,T3> oggetto restituito ComputeStatistics dal metodo.These values are stored in the Tuple<T1,T2,T3> object that is returned by the ComputeStatistics method. La Item3 proprietà contiene la deviazione standard.The Item3 property contains the standard deviation.

using System;

public class Example
{
   public static void Main()
   {
      Tuple<string, double, int>[] scores = 
                    { Tuple.Create("Jack", 78.8, 8),
                      Tuple.Create("Abbey", 92.1, 9), 
                      Tuple.Create("Dave", 88.3, 9),
                      Tuple.Create("Sam", 91.7, 8), 
                      Tuple.Create("Ed", 71.2, 5),
                      Tuple.Create("Penelope", 82.9, 8),
                      Tuple.Create("Linda", 99.0, 9),
                      Tuple.Create("Judith", 84.3, 9) };
      var result = ComputeStatistics(scores);
      Console.WriteLine("Mean score: {0:N2} (SD={1:N2}) (n={2})", 
                        result.Item2, result.Item3, result.Item1);
   }

   private static Tuple<int, double, double> ComputeStatistics(Tuple<string, double, int>[] scores) 
   {
      int n = 0;
      double sum = 0;

      // Compute the mean.
      foreach (var score in scores)
      {
         n += score.Item3;
         sum += score.Item2 * score.Item3;
      }
      double mean = sum / n;
      
      // Compute the standard deviation.
      double ss = 0;
      foreach (var score in scores)
      {
         ss = Math.Pow(score.Item2 - mean, 2);
      }
      double sd = Math.Sqrt(ss/scores.Length);
      return Tuple.Create(scores.Length, mean, sd);
   }
}
// The example displays the following output:
//       Mean score: 87.02 (SD=0.96) (n=8)
Module Example
   Public Sub Main()
      Dim scores() = 
                      { Tuple.Create("Jack", 78.8, 8),
                        Tuple.Create("Abbey", 92.1, 9), 
                        Tuple.Create("Dave", 88.3, 9),
                        Tuple.Create("Sam", 91.7, 8), 
                        Tuple.Create("Ed", 71.2, 5),
                        Tuple.Create("Penelope", 82.9, 8),
                        Tuple.Create("Linda", 99.0, 9),
                        Tuple.Create("Judith", 84.3, 9) }
      Dim result = ComputeStatistics(scores)
      Console.WriteLine("Mean score: {0:N2} (SD={1:N2}) (n={2})", 
                        result.Item2, result.Item3, result.Item1)
   End Sub
   
   Private Function ComputeStatistics(scores() As Tuple(Of String, Double, Integer)) _ 
                                As Tuple(Of Integer, Double, Double)
      Dim n As Integer = 0      
      Dim sum As Double = 0
      
      ' Compute the mean.
      For Each score In scores
         n+= score.Item3 
         sum += score.Item2 * score.Item3
      Next     
      Dim mean As Double = sum / n

      ' Compute the standard deviation.
      Dim ss As Double = 0
      For Each score In scores
         ss = Math.Pow(score.Item2 - mean, 2)
      Next
      Dim sd As Double = Math.Sqrt(ss/scores.Length)
      Return Tuple.Create(scores.Length, mean, sd)
   End Function
End Module
' The example displays the following output:
'       Mean score: 87.02 (SD=0.96) (n=8)

Commenti

È possibile determinare in modo dinamico il tipo di Item3 componente in uno dei due modi seguenti:You can dynamically determine the type of the Item3 component in one of two ways:

  • Chiamando il GetType metodo sul valore restituito Item3 dalla proprietà.By calling the GetType method on the value returned by the Item3 property.

  • Tramite il recupero dell' Type oggetto che rappresenta l' Tuple<T1,T2,T3> oggetto e il recupero del terzo elemento dalla matrice restituita dal Type.GetGenericArguments metodo.By retrieving the Type object that represents the Tuple<T1,T2,T3> object, and retrieving the third element from the array that is returned by its Type.GetGenericArguments method.

Si applica a