LambdaExpression LambdaExpression LambdaExpression LambdaExpression Class

定義

public ref class LambdaExpression abstract : System::Linq::Expressions::Expression

public abstract class LambdaExpression : System.Linq.Expressions.Expression

type LambdaExpression = class
    inherit Expression

Public MustInherit Class LambdaExpression
Inherits Expression

継承

ObjectObjectObjectObject

ExpressionExpressionExpressionExpression

LambdaExpressionLambdaExpressionLambdaExpressionLambdaExpression

派生

Expression<TDelegate>Expression<TDelegate>Expression<TDelegate>Expression<TDelegate>

例

次の例では、 Lambdaメソッドを使用して、渡された引数に1を加算するラムダ式を表す式を作成する方法を示します。The following example demonstrates how to create an expression that represents a lambda expression that adds 1 to the passed argument by using the Lambda method.

// Add the following directive to your file:
// using System.Linq.Expressions;  

// A parameter for the lambda expression.
ParameterExpression paramExpr = Expression.Parameter(typeof(int), "arg");

// This expression represents a lambda expression
// that adds 1 to the parameter value.
LambdaExpression lambdaExpr = Expression.Lambda(
    Expression.Add(
        paramExpr,
        Expression.Constant(1)
    ),
    new List<ParameterExpression>() { paramExpr }
);

// Print out the expression.
Console.WriteLine(lambdaExpr);

// Compile and run the lamda expression.
// The value of the parameter is 1.
Console.WriteLine(lambdaExpr.Compile().DynamicInvoke(1));

// This code example produces the following output:
//
// arg => (arg +1)
// 2

' Add the following directive to your file:
' Imports System.Linq.Expressions  

' A parameter for the lambda expression.
Dim paramExpr As ParameterExpression = Expression.Parameter(GetType(Integer), "arg")

' This expression represents a lambda expression
' that adds 1 to the parameter value.
Dim lambdaExpr As LambdaExpression = Expression.Lambda(
        Expression.Add(
            paramExpr,
            Expression.Constant(1)
        ),
        New List(Of ParameterExpression)() From {paramExpr}
    )

' Print out the expression.
Console.WriteLine(lambdaExpr)

' Compile and run the lamda expression.
' The value of the parameter is 1.
Console.WriteLine(lambdaExpr.Compile().DynamicInvoke(1))

' This code example produces the following output:
'
' arg => (arg +1)
' 2

注釈

型LambdaExpressionは、式ツリーの形式のラムダ式を表します。The LambdaExpression type represents a lambda expression in the form of an expression tree. Expression<TDelegate> からLambdaExpression派生し、ラムダ式の型をより明示的にキャプチャする型は、ラムダ式を表すためにも使用できます。The Expression<TDelegate> type, which derives from LambdaExpression and captures the type of the lambda expression more explicitly, can also be used to represent a lambda expression. 実行時には、ラムダ式を表す式ツリーノードは常に型Expression<TDelegate>になります。At runtime, an expression tree node that represents a lambda expression is always of type Expression<TDelegate>.

NodeTypeのプロパティの値Lambdaがです。 LambdaExpressionThe value of the NodeType property of a LambdaExpression is Lambda.

ファクトリメソッドLambdaを使用してオブジェクトLambdaExpressionを作成します。Use the Lambda factory methods to create a LambdaExpression object.

プロパティ

メソッド

適用対象