LambdaExpression LambdaExpression LambdaExpression LambdaExpression Class

定義

public ref class LambdaExpression abstract : System::Linq::Expressions::Expression

public abstract class LambdaExpression : System.Linq.Expressions.Expression

type LambdaExpression = class
    inherit Expression

Public MustInherit Class LambdaExpression
Inherits Expression

継承

ObjectObjectObjectObject

ExpressionExpressionExpressionExpression

LambdaExpressionLambdaExpressionLambdaExpressionLambdaExpression

派生

System.Linq.Expressions.Expression<TDelegate>System.Linq.Expressions.Expression<TDelegate>System.Linq.Expressions.Expression<TDelegate>System.Linq.Expressions.Expression<TDelegate>

例

次の例では、1 を使用して、渡された引数に追加するラムダ式を表す式を作成する方法、Lambdaメソッド。The following example demonstrates how to create an expression that represents a lambda expression that adds 1 to the passed argument by using the Lambda method.

// Add the following directive to your file:
// using System.Linq.Expressions;  

// A parameter for the lambda expression.
ParameterExpression paramExpr = Expression.Parameter(typeof(int), "arg");

// This expression represents a lambda expression
// that adds 1 to the parameter value.
LambdaExpression lambdaExpr = Expression.Lambda(
    Expression.Add(
        paramExpr,
        Expression.Constant(1)
    ),
    new List<ParameterExpression>() { paramExpr }
);

// Print out the expression.
Console.WriteLine(lambdaExpr);

// Compile and run the lamda expression.
// The value of the parameter is 1.
Console.WriteLine(lambdaExpr.Compile().DynamicInvoke(1));

// This code example produces the following output:
//
// arg => (arg +1)
// 2

' Add the following directive to your file:
' Imports System.Linq.Expressions  

' A parameter for the lambda expression.
Dim paramExpr As ParameterExpression = Expression.Parameter(GetType(Integer), "arg")

' This expression represents a lambda expression
' that adds 1 to the parameter value.
Dim lambdaExpr As LambdaExpression = Expression.Lambda(
        Expression.Add(
            paramExpr,
            Expression.Constant(1)
        ),
        New List(Of ParameterExpression)() From {paramExpr}
    )

' Print out the expression.
Console.WriteLine(lambdaExpr)

' Compile and run the lamda expression.
' The value of the parameter is 1.
Console.WriteLine(lambdaExpr.Compile().DynamicInvoke(1))

' This code example produces the following output:
'
' arg => (arg +1)
' 2

注釈

LambdaExpression型が式ツリーの形式でのラムダ式を表します。The LambdaExpression type represents a lambda expression in the form of an expression tree. Expression<TDelegate>型から派生したLambdaExpressionの詳細は、明示的にこともできますをラムダ式を表すラムダ式の型をキャプチャします。The Expression<TDelegate> type, which derives from LambdaExpression and captures the type of the lambda expression more explicitly, can also be used to represent a lambda expression. 実行時に、ラムダ式を表す式ツリー ノードは常に型のExpression<TDelegate>します。At runtime, an expression tree node that represents a lambda expression is always of type Expression<TDelegate>.

値、NodeTypeのプロパティをLambdaExpressionはLambdaします。The value of the NodeType property of a LambdaExpression is Lambda.

使用して、Lambda作成するファクトリ メソッドをLambdaExpressionオブジェクト。Use the Lambda factory methods to create a LambdaExpression object.

プロパティ

方法

適用対象