Double.MinValue Double.MinValue Double.MinValue Double.MinValue Field

정의

Double의 최소값을 나타냅니다.Represents the smallest possible value of a Double. 이 필드는 상수입니다.This field is constant.

public: double MinValue = -1.79769313486232E+308;
public const double MinValue = -1.79769313486232E+308;
val mutable MinValue : double
Public Const MinValue As Double  = -1.79769313486232E+308

필드 값

예제

다음 코드 예제에서는 MinValue:The following code example illustrates the use of MinValue:

public ref class Temperature
{
public:
   static property double MinValue 
   {
      double get()
      {
         return Double::MinValue;
      }
   }

   static property double MaxValue 
   {
      double get()
      {
         return Double::MaxValue;
      }
   }

protected:
   // The value holder
   double m_value;

public:
   property double Value 
   {
      double get()
      {
         return m_value;
      }
      void set( double value )
      {
         m_value = value;
      }
   }

   property double Celsius 
   {
      double get()
      {
         return (m_value - 32.0) / 1.8;
      }
      void set( double value )
      {
         m_value = 1.8 * value + 32.0;
      }
   }
};
public class Temperature {
	public static double MinValue {
		get {
			return Double.MinValue;
		}
	}

	public static double MaxValue {
		get {
			return Double.MaxValue;
		}
	}

	// The value holder
	protected double m_value;

	public double Value {
		get {
			return m_value;
		}
		set {
			m_value = value;
		}
	}

	public double Celsius {
		get {
			return (m_value-32.0)/1.8;
		}
		set {
			m_value = 1.8*value+32.0;
		}
	}
}
Public Class Temperature

    Public Shared ReadOnly Property MinValue() As Double
        Get
            Return Double.MinValue
        End Get
    End Property

    Public Shared ReadOnly Property MaxValue() As Double
        Get
            Return Double.MaxValue
        End Get
    End Property

    ' The value holder
    Protected m_value As Double

    Public Property Value() As Double
        Get
            Return m_value
        End Get
        Set(ByVal Value As Double)
            m_value = Value
        End Set
    End Property

    Public Property Celsius() As Double
        Get
            Return (m_value - 32) / 1.8
        End Get
        Set(ByVal Value As Double)
            m_value = Value * 1.8 + 32
        End Set
    End Property
End Class

설명

이 상수의 값은 음수 1.7976931348623157 e + 308입니다.The value of this constant is negative 1.7976931348623157E+308.

작업의 결과 보다 작은 Double.MinValueDouble.NegativeInfinity합니다.The result of an operation that is less than Double.MinValue is Double.NegativeInfinity. 다음 예에서 Double.NegativeInfinity 결과가 빼기 및 곱하기 연산에서 결과 보다 작은 Double.MinValue합니다.In the following example, Double.NegativeInfinity results from subtraction and multiplication operations when the result is less than Double.MinValue.

using System;

public class Example
{
   public static void Main()
   {
      double result1 = -7.997e307 + -9.985e307;
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result1, Double.IsNegativeInfinity(result1));
      
      double result2 = -1.5935e250 * 7.948e110;
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result2, Double.IsNegativeInfinity(result2));
   }
}
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)
Module Example
   Public Sub Main()
      Dim result1 As Double = -7.997e307 + -9.985e307
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result1, Double.IsNegativeInfinity(result1))
      
      Dim result2 As Double = -1.5935e250 * 7.948e110
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result2, Double.IsNegativeInfinity(result2))
   End Sub
End Module
' The example displays the following output:
'    -Infinity (Negative Infinity: True)
'    -Infinity (Negative Infinity: True)

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