DateTime.AddSeconds(Double) DateTime.AddSeconds(Double) DateTime.AddSeconds(Double) DateTime.AddSeconds(Double) Method

定义

返回一个新的 DateTime,它将指定的秒数加到此实例的值上。Returns a new DateTime that adds the specified number of seconds to the value of this instance.

public:
 DateTime AddSeconds(double value);
public DateTime AddSeconds (double value);
member this.AddSeconds : double -> DateTime
Public Function AddSeconds (value As Double) As DateTime

参数

value
Double Double Double Double

由整数和小数部分组成的秒数。A number of whole and fractional seconds. value 参数可以是负数也可以是正数。The value parameter can be negative or positive.

返回

一个对象,其值是此实例所表示的日期和时间与 value 所表示的秒数之和。An object whose value is the sum of the date and time represented by this instance and the number of seconds represented by value.

异常

示例

下面的示例使用AddSeconds方法将30秒和一天中的秒数加DateTime到值中。The following example uses the AddSeconds method to add 30 seconds and the number of seconds in one day to a DateTime value. 然后,它显示每个新值,并显示它与原始值之间的差异。It then displays each new value and displays the difference between it and the original value. 差异同时显示为时间跨度和刻度数。The difference is displayed both as a time span and as a number of ticks.

using System;

public class Example
{
   public static void Main()
   {
      string dateFormat = "MM/dd/yyyy hh:mm:ss";
      DateTime date1 = new DateTime(2014, 9, 8, 16, 0, 0);
      Console.WriteLine("Original date: {0} ({1:N0} ticks)\n",
                        date1.ToString(dateFormat), date1.Ticks);
      
      DateTime date2 = date1.AddSeconds(30);
      Console.WriteLine("Second date:   {0} ({1:N0} ticks)",
                        date2.ToString(dateFormat), date2.Ticks);
      Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)\n",
                        date2 - date1, date2.Ticks - date1.Ticks);                        
      
      // Add 1 day's worth of seconds (60 secs. * 60 mins * 24 hrs.
      DateTime date3 = date1.AddSeconds(60 * 60 * 24);
      Console.WriteLine("Third date:    {0} ({1:N0} ticks)",
                        date3.ToString(dateFormat), date3.Ticks);
      Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)",
                        date3 - date1, date3.Ticks - date1.Ticks);                        
   }
}
// The example displays the following output:
//    Original date: 09/08/2014 04:00:00 (635,457,888,000,000,000 ticks)
//
//    Second date:   09/08/2014 04:00:30 (635,457,888,300,000,000 ticks)
//    Difference between dates: 00:00:30 (300,000,000 ticks)
//
//    Third date:    09/09/2014 04:00:00 (635,458,752,000,000,000 ticks)
//    Difference between dates: 1.00:00:00 (864,000,000,000 ticks)
Module Example
   Public Sub Main()
      Dim dateFormat As String = "MM/dd/yyyy hh:mm:ss"
      Dim date1 As Date = #09/08/2014 16:00#
      Console.WriteLine("Original date: {0} ({1:N0} ticks)", _
                        date1.ToString(dateFormat), date1.Ticks)
      Console.WriteLine()
      
      Dim date2 As Date = date1.AddSeconds(30)
      Console.WriteLine("Second date:   {0} ({1:N0} ticks)", _
                        date2.ToString(dateFormat), date2.Ticks)
      Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)", _
                        date2 - date1, date2.Ticks - date1.Ticks)                        
      Console.WriteLine()
      
      ' Add 1 day's worth of seconds (60 secs. * 60 mins * 24 hrs.
      Dim date3 As Date = date1.AddSeconds(60 * 60 * 24)
      Console.WriteLine("Third date:    {0} ({1:N0} ticks)", _
                        date3.ToString(dateFormat), date3.Ticks)
      Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)", _
                        date3 - date1, date3.Ticks - date1.Ticks)                        
   End Sub
End Module
' The example displays the following output:
'    Original date: 09/08/2014 04:00:00 (635,457,888,000,000,000 ticks)
'
'    Second date:   09/08/2014 04:00:30 (635,457,888,300,000,000 ticks)
'    Difference between dates: 00:00:30 (300,000,000 ticks)
'
'    Third date:    09/09/2014 04:00:00 (635,458,752,000,000,000 ticks)
'    Difference between dates: 1.00:00:00 (864,000,000,000 ticks)

注解

此方法不更改此DateTime的值。This method does not change the value of this DateTime. 相反,它会返回一个DateTime新的,其值为此操作的结果。Instead, it returns a new DateTime whose value is the result of this operation.

的小数部分value是秒的小数部分。The fractional part of value is the fractional part of a second. 例如,4.5 等效于4秒,500毫秒,0刻度。For example, 4.5 is equivalent to 4 seconds, 500 milliseconds, and 0 ticks.

value参数舍入为最接近的毫秒。The value parameter is rounded to the nearest millisecond.

适用于

另请参阅