Enumerable.ToList<TSource>(IEnumerable<TSource>) 方法

定义

IEnumerable<T> 创建一个 List<T>

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Collections::Generic::List<TSource> ^ ToList(System::Collections::Generic::IEnumerable<TSource> ^ source);
public static System.Collections.Generic.List<TSource> ToList<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);
static member ToList : seq<'Source> -> System.Collections.Generic.List<'Source>
<Extension()>
Public Function ToList(Of TSource) (source As IEnumerable(Of TSource)) As List(Of TSource)

类型参数

TSource

source 的元素类型。

参数

source
IEnumerable<TSource>

要从其创建 List<T>IEnumerable<T>

返回

List<TSource>

一个包含输入序列中的元素的 List<T>

例外

sourcenull

示例

下面的代码示例演示如何使用 ToList 强制立即查询计算并返回 List<T> 包含查询结果的 。

string[] fruits = { "apple", "passionfruit", "banana", "mango",
                      "orange", "blueberry", "grape", "strawberry" };

List<int> lengths = fruits.Select(fruit => fruit.Length).ToList();

foreach (int length in lengths)
{
    Console.WriteLine(length);
}

/*
 This code produces the following output:

 5
 12
 6
 5
 6
 9
 5
 10
*/
' Create an array of strings.
Dim fruits() As String =
{"apple", "passionfruit", "banana", "mango",
 "orange", "blueberry", "grape", "strawberry"}

' Project the length of each string and
' put the length values into a List object.
Dim lengths As List(Of Integer) =
fruits _
.Select(Function(fruit) fruit.Length) _
.ToList()

' Display the results.
Dim output As New System.Text.StringBuilder
For Each length As Integer In lengths
    output.AppendLine(length)
Next
Console.WriteLine(output.ToString())

' This code produces the following output:
'
' 5
' 12
' 6
' 5
' 6
' 9
' 5
' 10

注解

方法 ToList<TSource>(IEnumerable<TSource>) 强制立即进行查询计算,并返回包含 List<T> 查询结果的 。 可以将此方法追加到查询中,以获取查询结果的缓存副本。

ToArray 具有类似的行为,但返回数组而不是 List<T>

适用于