# Table.PositionOf

## Syntax

```Table.PositionOf(table as table, row as record, optional occurrence as any, optional equationCriteria as any) as any
```

Returns the row position of the first occurrence of the `row` in the `table` specified. Returns -1 if no occurrence is found.

• `table`: The input table.
• `row`: The row in the table to find the position of.
• `occurrence`: [Optional] Specifies which occurrences of the row to return.
• `equationCriteria`: [Optional] Controls the comparison between the table rows.

## Example 1

Find the position of the first occurrence of [a = 2, b = 4] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})`.

``````Table.PositionOf(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
[a = 2, b = 4]
)
``````

`0`

## Example 2

Find the position of the second occurrence of [a = 2, b = 4] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})`.

``````Table.PositionOf(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
[a = 2, b = 4],
1
)
``````

`2`

## Example 3

Find the position of all the occurrences of [a = 2, b = 4] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})`.

``````Table.PositionOf(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
[a = 2, b = 4],
Occurrence.All
)
``````
 0 2