Enumerable.Max Méthode

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Max(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);

public static float? Max (this System.Collections.Generic.IEnumerable<float?> source);

static member Max : seq<Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

Paramètres

Retours

Nullable<Single>

Valeur de type Nullable<Single> en C# ou Nullable(Of Single) en Visual Basic qui correspond à la valeur maximale de la séquence.A value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Nullable<Double>>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Remarques

La Max(IEnumerable<Nullable<Single>>) méthode utilise l' Single implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

Si la séquence source est vide ou contient uniquement des valeurs qui sont null , cette fonction retourne null .If the source sequence is empty or contains only values that are null, this function returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static int Max(System::Collections::Generic::IEnumerable<int> ^ source);

public static int Max (this System.Collections.Generic.IEnumerable<int> source);

static member Max : seq<int> -> int

<Extension()>
Public Function Max (source As IEnumerable(Of Integer)) As Integer

Paramètres

Retours

Int32

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Int64>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Remarques

La Max(IEnumerable<Int32>) méthode utilise l' Int32 implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Max(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);

public static long? Max (this System.Collections.Generic.IEnumerable<long?> source);

static member Max : seq<Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

Paramètres

Retours

Nullable<Int64>

Valeur de type Nullable<Int64> en C# ou Nullable(Of Int64) en Visual Basic qui correspond à la valeur maximale de la séquence.A value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Nullable<Double>>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Remarques

La Max(IEnumerable<Nullable<Int64>>) méthode utilise l' Int64 implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

Si la séquence source est vide ou contient uniquement des valeurs qui sont null , cette fonction retourne null .If the source sequence is empty or contains only values that are null, this function returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static float Max(System::Collections::Generic::IEnumerable<float> ^ source);

public static float Max (this System.Collections.Generic.IEnumerable<float> source);

static member Max : seq<single> -> single

<Extension()>
Public Function Max (source As IEnumerable(Of Single)) As Single

Paramètres

Retours

Single

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Int64>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Remarques

La Max(IEnumerable<Single>) méthode utilise l' Single implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Single>) method uses the Single implementation of IComparable<T> to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Max(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);

public static int? Max (this System.Collections.Generic.IEnumerable<int?> source);

static member Max : seq<Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

Paramètres

Retours

Nullable<Int32>

Valeur de type Nullable<Int32> en C# ou Nullable(Of Int32) en Visual Basic qui correspond à la valeur maximale de la séquence.A value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Nullable<Double>>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Remarques

La Max(IEnumerable<Nullable<Int32>>) méthode utilise l' Int32 implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

Si la séquence source est vide ou contient uniquement des valeurs qui sont null , cette fonction retourne null .If the source sequence is empty or contains only values that are null, this function returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Max(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);

public static decimal Max (this System.Collections.Generic.IEnumerable<decimal> source);

static member Max : seq<decimal> -> decimal

<Extension()>
Public Function Max (source As IEnumerable(Of Decimal)) As Decimal

Paramètres

Retours

Decimal

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Int64>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Remarques

La Max(IEnumerable<Decimal>) méthode utilise l' Decimal implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Max(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);

public static decimal? Max (this System.Collections.Generic.IEnumerable<decimal?> source);

static member Max : seq<Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

Paramètres

Retours

Nullable<Decimal>

Valeur de type Nullable<Decimal> en C# ou Nullable(Of Decimal) en Visual Basic qui correspond à la valeur maximale de la séquence.A value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Nullable<Double>>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Remarques

La Max(IEnumerable<Nullable<Decimal>>) méthode utilise l' Decimal implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

Si la séquence source est vide ou contient uniquement des valeurs qui sont null , cette fonction retourne null .If the source sequence is empty or contains only values that are null, this function returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static long Max(System::Collections::Generic::IEnumerable<long> ^ source);

public static long Max (this System.Collections.Generic.IEnumerable<long> source);

static member Max : seq<int64> -> int64

<Extension()>
Public Function Max (source As IEnumerable(Of Long)) As Long

Paramètres

Retours

Int64

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Int64>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Remarques

La Max(IEnumerable<Int64>) méthode utilise l' Int64 implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static double Max(System::Collections::Generic::IEnumerable<double> ^ source);

public static double Max (this System.Collections.Generic.IEnumerable<double> source);

static member Max : seq<double> -> double

<Extension()>
Public Function Max (source As IEnumerable(Of Double)) As Double

Paramètres

Retours

Double

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Int64>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Remarques

La Max(IEnumerable<Double>) méthode utilise l' Double implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Max(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);

public static double? Max (this System.Collections.Generic.IEnumerable<double?> source);

static member Max : seq<Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

Paramètres

Retours

Nullable<Double>

Valeur de type Nullable<Double> en C# ou Nullable(Of Double) en Visual Basic qui correspond à la valeur maximale de la séquence.A value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max(IEnumerable<Nullable<Double>>) pour déterminer la valeur maximale dans une séquence.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Remarques

La Max(IEnumerable<Nullable<Double>>) méthode utilise l' Double implémentation de IComparable<T> pour comparer des valeurs.The Max(IEnumerable<Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

Si la séquence source est vide ou contient uniquement des valeurs qui sont null , cette fonction retourne null .If the source sequence is empty or contains only values that are null, this function returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource, typename TResult>
[System::Runtime::CompilerServices::Extension]
 static TResult Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, TResult> ^ selector);

public static TResult Max<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,TResult> selector);

public static TResult? Max<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,TResult> selector);

static member Max : seq<'Source> * Func<'Source, 'Result> -> 'Result

<Extension()>
Public Function Max(Of TSource, TResult) (source As IEnumerable(Of TSource), selector As Func(Of TSource, TResult)) As TResult

Paramètres de type

Paramètres

Retours

TResult

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

Si TResult le type implémente IComparable<T> , cette méthode utilise cette implémentation pour comparer les valeurs.If type TResult implements IComparable<T>, this method uses that implementation to compare values. Sinon, si le type TResult implémente IComparable , cette implémentation est utilisée pour comparer les valeurs.Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);

public static float Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);

static member Max : seq<'Source> * Func<'Source, single> -> single

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

Paramètres de type

Paramètres

Retours

Single

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Single>) méthode utilise l' Single implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method uses the Single implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Single .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);

public static float? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float?> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

Paramètres de type

Paramètres

Retours

Nullable<Single>

Valeur de type Nullable<Single> en C# ou Nullable(Of Single) en Visual Basic qui correspond à la valeur maximale de la séquence.The value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) méthode utilise l' Single implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Nullable<Single> en C# ou Nullable(Of Single) dans Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);

public static long? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long?> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

Paramètres de type

Paramètres

Retours

Nullable<Int64>

Valeur de type Nullable<Int64> en C# ou Nullable(Of Int64) en Visual Basic qui correspond à la valeur maximale de la séquence.The value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) méthode utilise l' Int64 implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Nullable<Int64> en C# ou Nullable(Of Int64) dans Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);

public static int? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int?> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

Paramètres de type

Paramètres

Retours

Nullable<Int32>

Valeur de type Nullable<Int32> en C# ou Nullable(Of Int32) en Visual Basic qui correspond à la valeur maximale de la séquence.The value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) méthode utilise l' Int32 implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Nullable<Int32> en C# ou Nullable(Of Int32) dans Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);

public static double? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double?> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

Paramètres de type

Paramètres

Retours

Nullable<Double>

Valeur de type Nullable<Double> en C# ou Nullable(Of Double) en Visual Basic qui correspond à la valeur maximale de la séquence.The value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) méthode utilise l' Double implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Nullable<Double> en C# ou Nullable(Of Double) dans Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);

public static long Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);

static member Max : seq<'Source> * Func<'Source, int64> -> int64

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

Paramètres de type

Paramètres

Retours

Int64

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) méthode utilise l' Int64 implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Int64 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);

public static int Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);

static member Max : seq<'Source> * Func<'Source, int> -> int

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

Paramètres de type

Paramètres

Retours

Int32

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) méthode utilise l' Int32 implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Int32 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);

public static double Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);

static member Max : seq<'Source> * Func<'Source, double> -> double

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

Paramètres de type

Paramètres

Retours

Double

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Double>) méthode utilise l' Double implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Double>) method uses the Double implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Double .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);

public static decimal Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);

static member Max : seq<'Source> * Func<'Source, decimal> -> decimal

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

Paramètres de type

Paramètres

Retours

Decimal

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) méthode utilise l' Decimal implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Decimal .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Max(System::Collections::Generic::IEnumerable<TSource> ^ source);

public static TSource Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);

public static TSource? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);

static member Max : seq<'Source> -> 'Source

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource)) As TSource

Paramètres de type

Paramètres

Retours

TSource

Valeur maximale dans la séquence.The maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>) pour déterminer la valeur maximale dans une séquence d' IComparable<T> objets.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>) to determine the maximum value in a sequence of IComparable<T> objects.

/// <summary>
/// This class implements IComparable to be able to
/// compare one Pet to another Pet.
/// </summary>
class Pet : IComparable<Pet>
{
    public string Name { get; set; }
    public int Age { get; set; }

    /// <summary>
    /// Compares this Pet to another Pet by
    /// summing each Pet's age and name length.
    /// </summary>
    /// <param name="other">The Pet to compare this Pet to.</param>
    /// <returns>-1 if this Pet is 'less' than the other Pet,
    /// 0 if they are equal,
    /// or 1 if this Pet is 'greater' than the other Pet.</returns>
    int IComparable<Pet>.CompareTo(Pet other)
    {
        int sumOther = other.Age + other.Name.Length;
        int sumThis = this.Age + this.Name.Length;

        if (sumOther > sumThis)
            return -1;
        else if (sumOther == sumThis)
            return 0;
        else
            return 1;
    }
}

public static void MaxEx3()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    Pet max = pets.Max();

    Console.WriteLine(
        "The 'maximum' animal is {0}.",
        max.Name);
}

/*
 This code produces the following output:

 The 'maximum' animal is Barley.
*/

' This class implements IComparable 
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' <summary>
    ''' Compares Pet objects by the sum of their age and name length.
    ''' </summary>
    ''' <param name="other">The Pet to compare this Pet to.</param>
    ''' <returns>-1 if this Pet's sum is 'less' than the other Pet,
    ''' 0 if they are equal,
    ''' or 1 if this Pet's sum is 'greater' than the other Pet.</returns>
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age + other.Name.Length > Me.Age + Me.Name.Length) Then
            Return -1
        ElseIf (other.Age + other.Name.Length = Me.Age + Me.Name.Length) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MaxEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the "maximum" pet according to the 
    ' custom CompareTo() implementation.
    Dim max As Pet = pets.Max()

    ' Display the result.
    Console.WriteLine($"The 'maximum' animal is {max.Name}")
End Sub

' This code produces the following output:
'
' The 'maximum' animal is Barley

Remarques

Si TSource le type implémente IComparable<T> , Max<TSource>(IEnumerable<TSource>) la méthode utilise cette implémentation pour comparer les valeurs.If type TSource implements IComparable<T>, the Max<TSource>(IEnumerable<TSource>) method uses that implementation to compare values. Sinon, si le type TSource implémente IComparable , cette implémentation est utilisée pour comparer les valeurs.Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

Si TSource est un type référence et que la séquence source est vide ou ne contient que des valeurs null , cette méthode retourne null .If TSource is a reference type and the source sequence is empty or contains only values that are null, this method returns null.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);

public static decimal? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal?> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

Paramètres de type

Paramètres

Retours

Nullable<Decimal>

Valeur de type Nullable<Decimal> en C# ou Nullable(Of Decimal) en Visual Basic qui correspond à la valeur maximale de la séquence.The value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the maximum value in the sequence.

Exceptions

Exemples

L’exemple de code suivant montre comment utiliser Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) pour déterminer la valeur maximale dans une séquence de valeurs projetées.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Remarques

La Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) méthode utilise l' Decimal implémentation de IComparable<T> pour comparer des valeurs.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

Vous pouvez appliquer cette méthode à une séquence de valeurs arbitraires si vous fournissez une fonction, selector , qui projette les membres de source dans un type numérique, en particulier Nullable<Decimal> en C# ou Nullable(Of Decimal) dans Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

Dans Visual Basic syntaxe d’expression de requête, une Aggregate Into Max() clause se traduit par un appel de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Voir aussi

• Aggregate, clause (Visual Basic)Aggregate Clause (Visual Basic)