ButtonType Wyliczenie

Definicja

Określa różne typy przycisków, które mogą być renderowane na stronie Web Forms.

public enum class ButtonType
public enum ButtonType
type ButtonType = 
Public Enum ButtonType
Dziedziczenie
ButtonType

Pola

Button 0

Przycisk polecenia.

Image 1

Przycisk, który wyświetla obraz.

2

Przycisk w stylu hiperłącza.

Przykłady

W poniższym przykładzie pokazano, jak za pomocą ButtonType wyliczenia określić, że przyciski linków są wyświetlane w ButtonField kolumnie pola kontrolki GridView . Właściwość ButtonType ButtonField obiektu jest deklaratywnie ustawiona na ButtonType.Linkwartość .


<%@ Page language="C#" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">

  void AuthorsGridView_RowCommand(Object sender, GridViewCommandEventArgs e)
  {
  
    // If multiple ButtonField column fields are used, use the
    // CommandName property to determine which button was clicked.
    if(e.CommandName=="Select")
    {
    
      // Convert the row index stored in the CommandArgument
      // property to an Integer.
      int index = Convert.ToInt32(e.CommandArgument);    
    
      // Get the last name of the selected author from the appropriate
      // cell in the GridView control.
      GridViewRow selectedRow = AuthorsGridView.Rows[index];
      TableCell lastNameCell = selectedRow.Cells[1];
      string lastName = lastNameCell.Text;  
    
      // Display the selected author.
      Message.Text = "You selected " + lastName + ".";
      
    }
    
  }
  
  void AuthorsGridView_RowCreated(Object sender, GridViewRowEventArgs e)
  {
    
    // The GridViewCommandEventArgs class does not contain a 
    // property that indicates which row's command button was
    // clicked. To identify which row contains the button 
    // clicked, use the button's CommandArgument property by 
    // setting it to the row's index.
    if(e.Row.RowType == DataControlRowType.DataRow)
    {
    
      // Retrieve the button control from the first column.
      // Because the ButtonType property of the column field
      // is set to ButtonType.Link, the button control must be
      // cast to a LinkButton. If you specify a different button
      // type, you must cast the button control to the appropriate
      // button type.
      LinkButton selectButton = (LinkButton)e.Row.Cells[0].Controls[0];
            
      // Set the LinkButton's CommandArgument property with the
      // row's index.
      selectButton.CommandArgument = e.Row.RowIndex.ToString();
      
    }

  }
    
</script>

<html xmlns="http://www.w3.org/1999/xhtml" >
  <head runat="server">
    <title>ButtonType Example</title>
</head>
<body>
    <form id="form1" runat="server">
        
      <h3>ButtonType Example</h3>
      
      <asp:label id="Message"
        forecolor="Red"
        runat="server"
        AssociatedControlID="AuthorsGridView"/>
                    
      <!-- Populate the Fields collection declaratively. -->
      <asp:gridview id="AuthorsGridView" 
        datasourceid="AuthorsSqlDataSource" 
        autogeneratecolumns="false"
        onrowcommand="AuthorsGridView_RowCommand" 
        runat="server">
                
        <columns>
                
          <asp:buttonfield buttontype="Link" commandname="Select" text="Select"/>
          <asp:boundfield datafield="au_lname" headertext="au_lname"/>
          <asp:boundfield datafield="au_fname" headertext="au_fname"/>
                
        </columns>
                
      </asp:gridview>
            
      <!-- This example uses Microsoft SQL Server and connects -->
      <!-- to the Pubs sample database.                        -->
      <asp:sqldatasource id="AuthorsSqlDataSource"  
        selectcommand="SELECT [au_lname], [au_fname] FROM [authors]"
        connectionstring="server=localhost;database=pubs;integrated security=SSPI"
        runat="server">
      </asp:sqldatasource>
            
    </form>
  </body>
</html>

<%@ Page language="VB" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">

  Sub AuthorsGridView_RowCommand(ByVal sender As Object, ByVal e As GridViewCommandEventArgs)
  
    ' If multiple ButtonField column fields are used, use the
    ' CommandName property to determine which button was clicked.
    If e.CommandName = "Select" Then
    
      ' Convert the row index stored in the CommandArgument
      ' property to an Integer.
      Dim index As Integer = Convert.ToInt32(e.CommandArgument)    
    
      ' Get the last name of the selected author from the appropriate
      ' cell in the GridView control.
      Dim selectedRow As GridViewRow = AuthorsGridView.Rows(index)
      Dim lastNameCell As TableCell = selectedRow.Cells(1)
      Dim lastName As String = lastNameCell.Text  
    
      ' Display the selected author.
      Message.Text = "You selected " & lastName & "."
      
    End If
    
  End Sub
  
  Sub AuthorsGridView_RowCreated(ByVal sender As Object, ByVal e As GridViewRowEventArgs)
    
    ' The GridViewCommandEventArgs class does not contain a 
    ' property that indicates which row's command button was
    ' clicked. To identify which row contains the button 
    ' clicked, use the button's CommandArgument property by 
    ' setting it to the row's index.
    If e.Row.RowType = DataControlRowType.DataRow Then
    
      ' Retrieve the button control from the first column.
      ' Because the ButtonType property of the column field
      ' is set to ButtonType.Link, the button control must be
      ' cast to a LinkButton. If you specify a different button
      ' type, you must cast the button control to the appropriate
      ' button type.
      Dim selectButton As LinkButton = CType(e.Row.Cells(0).Controls(0), LinkButton)
            
      ' Set the LinkButton's CommandArgument property with the
      ' row's index.
      selectButton.CommandArgument = e.Row.RowIndex.ToString()
      
    End If

  End Sub
    
</script>

<html xmlns="http://www.w3.org/1999/xhtml" >
  <head runat="server">
    <title>ButtonType Example</title>
</head>
<body>
    <form id="form1" runat="server">
        
      <h3>ButtonType Example</h3>
      
      <asp:label id="Message"
        forecolor="Red"
        runat="server"
        AssociatedControlID="AuthorsGridView"/>
                    
      <!-- Populate the Columns collection declaratively. -->
      <asp:gridview id="AuthorsGridView" 
        datasourceid="AuthorsSqlDataSource" 
        autogeneratecolumns="false"
        onrowcommand="AuthorsGridView_RowCommand" 
        runat="server">
                
        <columns>
                
          <asp:buttonfield buttontype="Link" commandname="Select" text="Select"/>
          <asp:boundfield datafield="au_lname" headertext="au_lname"/>
          <asp:boundfield datafield="au_fname" headertext="au_fname"/>
                
        </columns>
                
      </asp:gridview>
            
      <!-- This example uses Microsoft SQL Server and connects -->
      <!-- to the Pubs sample database.                        -->
      <asp:sqldatasource id="AuthorsSqlDataSource"  
        selectcommand="SELECT [au_lname], [au_fname] FROM [authors]"
        connectionstring="server=localhost;database=pubs;integrated security=SSPI"
        runat="server">
      </asp:sqldatasource>
            
    </form>
  </body>
</html>

Uwagi

Wyliczenie ButtonType służy do reprezentowania różnych typów przycisków (takich jak przycisk polecenia, przycisk obrazu, przycisk linku itd.), które mogą być renderowane na stronie ASP.NET. Jest on często używany przez właściwości, takie jak ButtonType właściwość ButtonFieldBase klasy, aby wskazać, który typ przycisku jest używany przez kontrolkę nadrzędną.

Dotyczy

Zobacz też