Double.IsNegativeInfinity(Double) 方法

定义

返回一个值,通过该值指示指定数字是否计算为负无穷大。Returns a value indicating whether the specified number evaluates to negative infinity.

public:
 static bool IsNegativeInfinity(double d);
public static bool IsNegativeInfinity (double d);
static member IsNegativeInfinity : double -> bool
Public Shared Function IsNegativeInfinity (d As Double) As Boolean

参数

d
Double

一个双精度浮点数。A double-precision floating-point number.

返回

如果 d 的计算结果为 NegativeInfinity,则为 true;否则为 falsetrue if d evaluates to NegativeInfinity; otherwise, false.

示例

下面的代码示例演示如何使用 IsNegativeInfinityThe following code example illustrates the use of IsNegativeInfinity:

// This will return S"true".
Console::WriteLine( "IsNegativeInfinity(-5.0 / 0) == {0}.", Double::IsNegativeInfinity(  -5.0 / zero ) ? (String^)"true" : "false" );
// This will return "true".
Console.WriteLine("IsNegativeInfinity(-5.0 / 0) == {0}.", Double.IsNegativeInfinity(-5.0 / 0) ? "true" : "false");
' This will return "True".
Console.Write("IsNegativeInfinity(-5.0 / 0) = ")
If Double.IsNegativeInfinity(-5 / 0) Then
    Console.WriteLine("True.")
Else
    Console.WriteLine("False.")
End If
if ( d > Double::MaxValue )
{
   Console::WriteLine( "Your number is bigger than a double." );
}
if (d > Double.MaxValue) 
   Console.WriteLine("Your number is bigger than a double.");
If D > Double.MaxValue Then
    Console.WriteLine("Your number is bigger than a double.")
End If
// This will equal Infinity.
Console::WriteLine( "10.0 minus NegativeInfinity equals {0}.", (10.0 - Double::NegativeInfinity) );
// This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals {0}.", (10.0 - Double.NegativeInfinity).ToString());
' This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals " + (10 - Double.NegativeInfinity).ToString() + ".")

注解

浮点运算返回 NegativeInfinity 以指示溢出情况。Floating-point operations return NegativeInfinity to signal an overflow condition.

适用于

另请参阅