Calendar.GetDayOfYear(DateTime) Metoda

Definicja

Gdy jest zastępowany w klasie pochodnej, zwraca dzień roku w określonym DateTime .When overridden in a derived class, returns the day of the year in the specified DateTime.

public:
 abstract int GetDayOfYear(DateTime time);
public abstract int GetDayOfYear (DateTime time);
abstract member GetDayOfYear : DateTime -> int
Public MustOverride Function GetDayOfYear (time As DateTime) As Integer

Parametry

time
DateTime

DateTimeDo odczytu.The DateTime to read.

Zwraca

Int32

Dodatnia liczba całkowita reprezentująca dzień roku w time parametrze.A positive integer that represents the day of the year in the time parameter.

Przykłady

Poniższy przykład kodu demonstruje składowe Calendar klasy.The following code example demonstrates the members of the Calendar class.

using namespace System;
using namespace System::Globalization;
void DisplayValues( Calendar^ myCal, DateTime myDT )
{
   Console::WriteLine( "   Era: {0}", myCal->GetEra( myDT ) );
   Console::WriteLine( "   Year: {0}", myCal->GetYear( myDT ) );
   Console::WriteLine( "   Month: {0}", myCal->GetMonth( myDT ) );
   Console::WriteLine( "   DayOfYear: {0}", myCal->GetDayOfYear( myDT ) );
   Console::WriteLine( "   DayOfMonth: {0}", myCal->GetDayOfMonth( myDT ) );
   Console::WriteLine( "   DayOfWeek: {0}", myCal->GetDayOfWeek( myDT ) );
   Console::WriteLine( "   Hour: {0}", myCal->GetHour( myDT ) );
   Console::WriteLine( "   Minute: {0}", myCal->GetMinute( myDT ) );
   Console::WriteLine( "   Second: {0}", myCal->GetSecond( myDT ) );
   Console::WriteLine( "   Milliseconds: {0}", myCal->GetMilliseconds( myDT ) );
   Console::WriteLine();
}

int main()
{
   
   // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
   DateTime myDT = DateTime(2002,4,3,gcnew GregorianCalendar);
   
   // Uses the default calendar of the InvariantCulture.
   Calendar^ myCal = CultureInfo::InvariantCulture->Calendar;
   
   // Displays the values of the DateTime.
   Console::WriteLine( "April 3, 2002 of the Gregorian calendar:" );
   DisplayValues( myCal, myDT );
   
   // Adds 5 to every component of the DateTime.
   myDT = myCal->AddYears( myDT, 5 );
   myDT = myCal->AddMonths( myDT, 5 );
   myDT = myCal->AddWeeks( myDT, 5 );
   myDT = myCal->AddDays( myDT, 5 );
   myDT = myCal->AddHours( myDT, 5 );
   myDT = myCal->AddMinutes( myDT, 5 );
   myDT = myCal->AddSeconds( myDT, 5 );
   myDT = myCal->AddMilliseconds( myDT, 5 );
   
   // Displays the values of the DateTime.
   Console::WriteLine( "After adding 5 to each component of the DateTime:" );
   DisplayValues( myCal, myDT );
}

/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar:
Era:          1
Year:         2002
Month:        4
DayOfYear:    93
DayOfMonth:   3
DayOfWeek:    Wednesday
Hour:         0
Minute:       0
Second:       0
Milliseconds: 0

After adding 5 to each component of the DateTime:
Era:          1
Year:         2007
Month:        10
DayOfYear:    286
DayOfMonth:   13
DayOfWeek:    Saturday
Hour:         5
Minute:       5
Second:       5
Milliseconds: 5

*/
using System;
using System.Globalization;

public class SamplesCalendar  {

   public static void Main()  {

      // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      DateTime myDT = new DateTime( 2002, 4, 3, new GregorianCalendar() );

      // Uses the default calendar of the InvariantCulture.
      Calendar myCal = CultureInfo.InvariantCulture.Calendar;

      // Displays the values of the DateTime.
      Console.WriteLine( "April 3, 2002 of the Gregorian calendar:" );
      DisplayValues( myCal, myDT );

      // Adds 5 to every component of the DateTime.
      myDT = myCal.AddYears( myDT, 5 );
      myDT = myCal.AddMonths( myDT, 5 );
      myDT = myCal.AddWeeks( myDT, 5 );
      myDT = myCal.AddDays( myDT, 5 );
      myDT = myCal.AddHours( myDT, 5 );
      myDT = myCal.AddMinutes( myDT, 5 );
      myDT = myCal.AddSeconds( myDT, 5 );
      myDT = myCal.AddMilliseconds( myDT, 5 );

      // Displays the values of the DateTime.
      Console.WriteLine( "After adding 5 to each component of the DateTime:" );
      DisplayValues( myCal, myDT );
   }

   public static void DisplayValues( Calendar myCal, DateTime myDT )  {
      Console.WriteLine( "   Era:          {0}", myCal.GetEra( myDT ) );
      Console.WriteLine( "   Year:         {0}", myCal.GetYear( myDT ) );
      Console.WriteLine( "   Month:        {0}", myCal.GetMonth( myDT ) );
      Console.WriteLine( "   DayOfYear:    {0}", myCal.GetDayOfYear( myDT ) );
      Console.WriteLine( "   DayOfMonth:   {0}", myCal.GetDayOfMonth( myDT ) );
      Console.WriteLine( "   DayOfWeek:    {0}", myCal.GetDayOfWeek( myDT ) );
      Console.WriteLine( "   Hour:         {0}", myCal.GetHour( myDT ) );
      Console.WriteLine( "   Minute:       {0}", myCal.GetMinute( myDT ) );
      Console.WriteLine( "   Second:       {0}", myCal.GetSecond( myDT ) );
      Console.WriteLine( "   Milliseconds: {0}", myCal.GetMilliseconds( myDT ) );
      Console.WriteLine();
   }
}


/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar:
   Era:          1
   Year:         2002
   Month:        4
   DayOfYear:    93
   DayOfMonth:   3
   DayOfWeek:    Wednesday
   Hour:         0
   Minute:       0
   Second:       0
   Milliseconds: 0

After adding 5 to each component of the DateTime:
   Era:          1
   Year:         2007
   Month:        10
   DayOfYear:    286
   DayOfMonth:   13
   DayOfWeek:    Saturday
   Hour:         5
   Minute:       5
   Second:       5
   Milliseconds: 5

*/
Imports System.Globalization


Public Class SamplesCalendar   

   Public Shared Sub Main()

      ' Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      Dim myDT As New DateTime(2002, 4, 3, New GregorianCalendar())

      ' Uses the default calendar of the InvariantCulture.
      Dim myCal As Calendar = CultureInfo.InvariantCulture.Calendar

      ' Displays the values of the DateTime.
      Console.WriteLine("April 3, 2002 of the Gregorian calendar:")
      DisplayValues(myCal, myDT)

      ' Adds 5 to every component of the DateTime.
      myDT = myCal.AddYears(myDT, 5)
      myDT = myCal.AddMonths(myDT, 5)
      myDT = myCal.AddWeeks(myDT, 5)
      myDT = myCal.AddDays(myDT, 5)
      myDT = myCal.AddHours(myDT, 5)
      myDT = myCal.AddMinutes(myDT, 5)
      myDT = myCal.AddSeconds(myDT, 5)
      myDT = myCal.AddMilliseconds(myDT, 5)

      ' Displays the values of the DateTime.
      Console.WriteLine("After adding 5 to each component of the DateTime:")
      DisplayValues(myCal, myDT)

   End Sub

   Public Shared Sub DisplayValues(myCal As Calendar, myDT As DateTime)
      Console.WriteLine("   Era:          {0}", myCal.GetEra(myDT))
      Console.WriteLine("   Year:         {0}", myCal.GetYear(myDT))
      Console.WriteLine("   Month:        {0}", myCal.GetMonth(myDT))
      Console.WriteLine("   DayOfYear:    {0}", myCal.GetDayOfYear(myDT))
      Console.WriteLine("   DayOfMonth:   {0}", myCal.GetDayOfMonth(myDT))
      Console.WriteLine("   DayOfWeek:    {0}", myCal.GetDayOfWeek(myDT))
      Console.WriteLine("   Hour:         {0}", myCal.GetHour(myDT))
      Console.WriteLine("   Minute:       {0}", myCal.GetMinute(myDT))
      Console.WriteLine("   Second:       {0}", myCal.GetSecond(myDT))
      Console.WriteLine("   Milliseconds: {0}", myCal.GetMilliseconds(myDT))
      Console.WriteLine()
   End Sub

End Class


'This code produces the following output.
'
'April 3, 2002 of the Gregorian calendar:
'   Era:          1
'   Year:         2002
'   Month:        4
'   DayOfYear:    93
'   DayOfMonth:   3
'   DayOfWeek:    Wednesday
'   Hour:         0
'   Minute:       0
'   Second:       0
'   Milliseconds: 0
'
'After adding 5 to each component of the DateTime:
'   Era:          1
'   Year:         2007
'   Month:        10
'   DayOfYear:    286
'   DayOfMonth:   13
'   DayOfWeek:    Saturday
'   Hour:         5
'   Minute:       5
'   Second:       5
'   Milliseconds: 5

Uwagi

Dzień roku jest definiowany jako liczba dni od pierwszego dnia roku.The day of the year is defined as the number of days from the first day of the year. Na przykład w GregorianCalendar GetDayOfYear przypadku 1 stycznia zwraca wartość 1, a GetDayOfYear 31 grudnia zwraca 365 w typowym roku lub 366 w roku przestępnym.For example, in GregorianCalendar, GetDayOfYear for January 1 returns 1, and GetDayOfYear for December 31 returns 365 in a common year or 366 in a leap year.

Dotyczy

Zobacz też