ButtonFieldBase.ButtonType Właściwość

Definicja

Pobiera lub ustawia typ przycisku do wyświetlenia w polu przycisku.

public:
 virtual property System::Web::UI::WebControls::ButtonType ButtonType { System::Web::UI::WebControls::ButtonType get(); void set(System::Web::UI::WebControls::ButtonType value); };
public virtual System.Web.UI.WebControls.ButtonType ButtonType { get; set; }
member this.ButtonType : System.Web.UI.WebControls.ButtonType with get, set
Public Overridable Property ButtonType As ButtonType

Wartość właściwości

ButtonType

Jedna z ButtonType wartości. Wartość domyślna to ButtonType.Link.

Wyjątki

Wartość właściwości ButtonType nie jest jedną z ButtonType wartości.

Przykłady

W poniższym przykładzie kodu pokazano, jak za pomocą ButtonType właściwości określić, że przyciski są wyświetlane w ButtonField obiekcie kontrolki GridView .

<%@ Page language="C#" %>

<script runat="server">

  void AuthorsGridView_RowCommand(Object sender, GridViewCommandEventArgs e)
  {
  
    // If multiple ButtonField column fields are used, use the
    // CommandName property to determine which button was clicked.
    if(e.CommandName=="Select")
    {
    
      // Convert the row index stored in the CommandArgument
      // property to an Integer.
      int index = Convert.ToInt32(e.CommandArgument);    
    
      // Get the last name of the selected author from the appropriate
      // cell in the GridView control.
      GridViewRow selectedRow = AuthorsGridView.Rows[index];
      TableCell lastNameCell = selectedRow.Cells[1];
      string lastName = lastNameCell.Text;  
    
      // Display the selected author.
      Message.Text = "You selected " + lastName + ".";
      
    }
    
  }
    
</script>

<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>ButtonFieldBase ButtonType Example</title>
</head>
<body>
  <form id="form1" runat="server">
  <div>

    <h3>ButtonFieldBase ButtonType Example</h3>

    <asp:label id="Message"
      forecolor="Red"
      runat="server"
      AssociatedControlID="AuthorsGridView" />
                    
    <!-- Populate the Columns collection declaratively. -->
    <asp:gridview id="AuthorsGridView" 
      datasourceid="AuthorsSqlDataSource" 
      autogeneratecolumns="false"
      onrowcommand="AuthorsGridView_RowCommand" 
      runat="server">
                
      <columns>
        <asp:buttonfield buttontype="Button" 
          commandname="Select"
          headertext="Select Author" 
          text="Select"/>
        <asp:boundfield datafield="au_lname" 
          headertext="Last Name"/>
        <asp:boundfield datafield="au_fname" 
          headertext="First Name"/>
      </columns>
                
    </asp:gridview>
            
    <!-- This example uses Microsoft SQL Server and connects -->
    <!-- to the Pubs sample database. -->
    <asp:sqldatasource id="AuthorsSqlDataSource"  
      selectcommand="SELECT [au_lname], [au_fname] FROM [authors]"
      connectionstring="server=localhost;database=pubs;integrated security=SSPI"
      runat="server">
    </asp:sqldatasource>

  </div>
  </form>
</body>
</html>

<%@ Page language="VB" %>

<script runat="server">

  Sub AuthorsGridView_RowCommand(ByVal sender As Object, ByVal e As GridViewCommandEventArgs)
  
    ' If multiple ButtonField column fields are used, use the
    ' CommandName property to determine which button was clicked.
    If e.CommandName = "Select" Then
    
      ' Convert the row index stored in the CommandArgument
      ' property to an Integer.
      Dim index As Integer = Convert.ToInt32(e.CommandArgument)
    
      ' Get the last name of the selected author from the appropriate
      ' cell in the GridView control.
      Dim selectedRow As GridViewRow = AuthorsGridView.Rows(index)
      Dim lastNameCell As TableCell = selectedRow.Cells(1)
      Dim lastName As String = lastNameCell.Text
    
      ' Display the selected author.
      Message.Text = "You selected " & lastName & "."
      
    End If
    
  End Sub
    
</script>

<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>ButtonFieldBase ButtonType Example</title>
</head>
<body>
  <form id="form1" runat="server">
  <div>
        
    <h3>ButtonFieldBase ButtonType Example</h3>

    <asp:label id="Message"
      forecolor="Red"
      runat="server"
      AssociatedControlID="AuthorsGridView"/>

    <!-- Populate the Columns collection declaratively. -->
    <asp:gridview id="AuthorsGridView" 
      datasourceid="AuthorsSqlDataSource" 
      autogeneratecolumns="false"
      onrowcommand="AuthorsGridView_RowCommand"
      runat="server">

      <columns>
        <asp:buttonfield buttontype="Button" 
          commandname="Select"
          headertext="Select Author" 
          text="Select"/>
        <asp:boundfield datafield="au_lname" 
          headertext="Last Name"/>
        <asp:boundfield datafield="au_fname" 
          headertext="First Name"/>
      </columns>

    </asp:gridview>

    <!-- This example uses Microsoft SQL Server and connects -->
    <!-- to the Pubs sample database.                        -->
    <asp:sqldatasource id="AuthorsSqlDataSource"  
      selectcommand="SELECT [au_lname], [au_fname] FROM [authors]"
      connectionstring="server=localhost;database=pubs;integrated security=SSPI"
      runat="server">
    </asp:sqldatasource>

  </div>
  </form>
</body>
</html>

Uwagi

Użyj właściwości , ButtonType aby określić typ przycisku wyświetlanego w polu przycisku. W poniższej tabeli wymieniono dostępne typy przycisków.

Wartość typu przycisku Wyświetla jako
Button Kontrolka przycisku.
Image Przycisk z obrazem.
Link Link.

Wartość tej właściwości jest przechowywana w stanie widoku.

Dotyczy

Zobacz też